Theorem f0dom0 6250

Description: A function is empty iff it has an empty domain. (Contributed by AV, 10-Feb-2019.)

Assertion

Ref	Expression
f0dom0	⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Proof of Theorem f0dom0

Step	Hyp	Ref	Expression
1		feq2 6188	. . . 4 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 ↔ 𝐹:∅⟶𝑌))
2		f0bi 6249	. . . . 5 ⊢ (𝐹:∅⟶𝑌 ↔ 𝐹 = ∅)
3	2	biimpi 206	. . . 4 ⊢ (𝐹:∅⟶𝑌 → 𝐹 = ∅)
4	1, 3	syl6bi 243	. . 3 ⊢ (𝑋 = ∅ → (𝐹:𝑋⟶𝑌 → 𝐹 = ∅))
5	4	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ → 𝐹 = ∅))
6		feq1 6187	. . . 4 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 ↔ ∅:𝑋⟶𝑌))
7		dm0 5494	. . . . 5 ⊢ dom ∅ = ∅
8		fdm 6212	. . . . 5 ⊢ (∅:𝑋⟶𝑌 → dom ∅ = 𝑋)
9	7, 8	syl5reqr 2809	. . . 4 ⊢ (∅:𝑋⟶𝑌 → 𝑋 = ∅)
10	6, 9	syl6bi 243	. . 3 ⊢ (𝐹 = ∅ → (𝐹:𝑋⟶𝑌 → 𝑋 = ∅))
11	10	com12 32	. 2 ⊢ (𝐹:𝑋⟶𝑌 → (𝐹 = ∅ → 𝑋 = ∅))
12	5, 11	impbid 202	1 ⊢ (𝐹:𝑋⟶𝑌 → (𝑋 = ∅ ↔ 𝐹 = ∅))

Syntax hints:   → wi 4   ↔ wb 196   = wceq 1632  ∅c0 4058  dom cdm 5266  ⟶wf 6045

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1871  ax-4 1886  ax-5 1988  ax-6 2054  ax-7 2090  ax-9 2148  ax-10 2168  ax-11 2183  ax-12 2196  ax-13 2391  ax-ext 2740  ax-sep 4933  ax-nul 4941  ax-pr 5055

This theorem depends on definitions:  df-bi 197  df-or 384  df-an 385  df-3an 1074  df-tru 1635  df-ex 1854  df-nf 1859  df-sb 2047  df-eu 2611  df-mo 2612  df-clab 2747  df-cleq 2753  df-clel 2756  df-nfc 2891  df-ral 3055  df-rex 3056  df-rab 3059  df-v 3342  df-dif 3718  df-un 3720  df-in 3722  df-ss 3729  df-nul 4059  df-if 4231  df-sn 4322  df-pr 4324  df-op 4328  df-br 4805  df-opab 4865  df-id 5174  df-xp 5272  df-rel 5273  df-cnv 5274  df-co 5275  df-dm 5276  df-rn 5277  df-fun 6051  df-fn 6052  df-f 6053

This theorem is referenced by:  swrdn0  13630  elfrlmbasn0  20308  mavmulsolcl  20559