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Mirrors > Home > MPE Home > Th. List > efgcpbllema | Structured version Visualization version GIF version |
Description: Lemma for efgrelex 18364. Define an auxiliary equivalence relation 𝐿 such that 𝐴𝐿𝐵 if there are sequences from 𝐴 to 𝐵 passing through the same reduced word. (Contributed by Mario Carneiro, 1-Oct-2015.) |
Ref | Expression |
---|---|
efgval.w | ⊢ 𝑊 = ( I ‘Word (𝐼 × 2𝑜)) |
efgval.r | ⊢ ∼ = ( ~FG ‘𝐼) |
efgval2.m | ⊢ 𝑀 = (𝑦 ∈ 𝐼, 𝑧 ∈ 2𝑜 ↦ 〈𝑦, (1𝑜 ∖ 𝑧)〉) |
efgval2.t | ⊢ 𝑇 = (𝑣 ∈ 𝑊 ↦ (𝑛 ∈ (0...(♯‘𝑣)), 𝑤 ∈ (𝐼 × 2𝑜) ↦ (𝑣 splice 〈𝑛, 𝑛, 〈“𝑤(𝑀‘𝑤)”〉〉))) |
efgred.d | ⊢ 𝐷 = (𝑊 ∖ ∪ 𝑥 ∈ 𝑊 ran (𝑇‘𝑥)) |
efgred.s | ⊢ 𝑆 = (𝑚 ∈ {𝑡 ∈ (Word 𝑊 ∖ {∅}) ∣ ((𝑡‘0) ∈ 𝐷 ∧ ∀𝑘 ∈ (1..^(♯‘𝑡))(𝑡‘𝑘) ∈ ran (𝑇‘(𝑡‘(𝑘 − 1))))} ↦ (𝑚‘((♯‘𝑚) − 1))) |
efgcpbllem.1 | ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
Ref | Expression |
---|---|
efgcpbllema | ⊢ (𝑋𝐿𝑌 ↔ (𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | oveq2 6821 | . . . . 5 ⊢ (𝑖 = 𝑋 → (𝐴 ++ 𝑖) = (𝐴 ++ 𝑋)) | |
2 | 1 | oveq1d 6828 | . . . 4 ⊢ (𝑖 = 𝑋 → ((𝐴 ++ 𝑖) ++ 𝐵) = ((𝐴 ++ 𝑋) ++ 𝐵)) |
3 | oveq2 6821 | . . . . 5 ⊢ (𝑗 = 𝑌 → (𝐴 ++ 𝑗) = (𝐴 ++ 𝑌)) | |
4 | 3 | oveq1d 6828 | . . . 4 ⊢ (𝑗 = 𝑌 → ((𝐴 ++ 𝑗) ++ 𝐵) = ((𝐴 ++ 𝑌) ++ 𝐵)) |
5 | 2, 4 | breqan12d 4820 | . . 3 ⊢ ((𝑖 = 𝑋 ∧ 𝑗 = 𝑌) → (((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵) ↔ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
6 | efgcpbllem.1 | . . . 4 ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} | |
7 | vex 3343 | . . . . . . 7 ⊢ 𝑖 ∈ V | |
8 | vex 3343 | . . . . . . 7 ⊢ 𝑗 ∈ V | |
9 | 7, 8 | prss 4496 | . . . . . 6 ⊢ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ↔ {𝑖, 𝑗} ⊆ 𝑊) |
10 | 9 | anbi1i 733 | . . . . 5 ⊢ (((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵)) ↔ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))) |
11 | 10 | opabbii 4869 | . . . 4 ⊢ {〈𝑖, 𝑗〉 ∣ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} = {〈𝑖, 𝑗〉 ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
12 | 6, 11 | eqtr4i 2785 | . . 3 ⊢ 𝐿 = {〈𝑖, 𝑗〉 ∣ ((𝑖 ∈ 𝑊 ∧ 𝑗 ∈ 𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ∼ ((𝐴 ++ 𝑗) ++ 𝐵))} |
13 | 5, 12 | brab2a 5351 | . 2 ⊢ (𝑋𝐿𝑌 ↔ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
14 | df-3an 1074 | . 2 ⊢ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵)) ↔ ((𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) | |
15 | 13, 14 | bitr4i 267 | 1 ⊢ (𝑋𝐿𝑌 ↔ (𝑋 ∈ 𝑊 ∧ 𝑌 ∈ 𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ∼ ((𝐴 ++ 𝑌) ++ 𝐵))) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 196 ∧ wa 383 ∧ w3a 1072 = wceq 1632 ∈ wcel 2139 ∀wral 3050 {crab 3054 ∖ cdif 3712 ⊆ wss 3715 ∅c0 4058 {csn 4321 {cpr 4323 〈cop 4327 〈cotp 4329 ∪ ciun 4672 class class class wbr 4804 {copab 4864 ↦ cmpt 4881 I cid 5173 × cxp 5264 ran crn 5267 ‘cfv 6049 (class class class)co 6813 ↦ cmpt2 6815 1𝑜c1o 7722 2𝑜c2o 7723 0cc0 10128 1c1 10129 − cmin 10458 ...cfz 12519 ..^cfzo 12659 ♯chash 13311 Word cword 13477 ++ cconcat 13479 splice csplice 13482 〈“cs2 13786 ~FG cefg 18319 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1871 ax-4 1886 ax-5 1988 ax-6 2054 ax-7 2090 ax-9 2148 ax-10 2168 ax-11 2183 ax-12 2196 ax-13 2391 ax-ext 2740 ax-sep 4933 ax-nul 4941 ax-pr 5055 |
This theorem depends on definitions: df-bi 197 df-or 384 df-an 385 df-3an 1074 df-tru 1635 df-ex 1854 df-nf 1859 df-sb 2047 df-eu 2611 df-mo 2612 df-clab 2747 df-cleq 2753 df-clel 2756 df-nfc 2891 df-ral 3055 df-rex 3056 df-rab 3059 df-v 3342 df-dif 3718 df-un 3720 df-in 3722 df-ss 3729 df-nul 4059 df-if 4231 df-sn 4322 df-pr 4324 df-op 4328 df-uni 4589 df-br 4805 df-opab 4865 df-xp 5272 df-iota 6012 df-fv 6057 df-ov 6816 |
This theorem is referenced by: efgcpbllemb 18368 efgcpbl 18369 |
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