![]() |
Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
|
Mirrors > Home > MPE Home > Th. List > csbhypf | Structured version Visualization version GIF version |
Description: Introduce an explicit substitution into an implicit substitution hypothesis. See sbhypf 3284 for class substitution version. (Contributed by NM, 19-Dec-2008.) |
Ref | Expression |
---|---|
csbhypf.1 | ⊢ Ⅎ𝑥𝐴 |
csbhypf.2 | ⊢ Ⅎ𝑥𝐶 |
csbhypf.3 | ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) |
Ref | Expression |
---|---|
csbhypf | ⊢ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | csbhypf.1 | . . . 4 ⊢ Ⅎ𝑥𝐴 | |
2 | 1 | nfeq2 2809 | . . 3 ⊢ Ⅎ𝑥 𝑦 = 𝐴 |
3 | nfcsb1v 3582 | . . . 4 ⊢ Ⅎ𝑥⦋𝑦 / 𝑥⦌𝐵 | |
4 | csbhypf.2 | . . . 4 ⊢ Ⅎ𝑥𝐶 | |
5 | 3, 4 | nfeq 2805 | . . 3 ⊢ Ⅎ𝑥⦋𝑦 / 𝑥⦌𝐵 = 𝐶 |
6 | 2, 5 | nfim 1865 | . 2 ⊢ Ⅎ𝑥(𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶) |
7 | eqeq1 2655 | . . 3 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝐴 ↔ 𝑦 = 𝐴)) | |
8 | csbeq1a 3575 | . . . 4 ⊢ (𝑥 = 𝑦 → 𝐵 = ⦋𝑦 / 𝑥⦌𝐵) | |
9 | 8 | eqeq1d 2653 | . . 3 ⊢ (𝑥 = 𝑦 → (𝐵 = 𝐶 ↔ ⦋𝑦 / 𝑥⦌𝐵 = 𝐶)) |
10 | 7, 9 | imbi12d 333 | . 2 ⊢ (𝑥 = 𝑦 → ((𝑥 = 𝐴 → 𝐵 = 𝐶) ↔ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶))) |
11 | csbhypf.3 | . 2 ⊢ (𝑥 = 𝐴 → 𝐵 = 𝐶) | |
12 | 6, 10, 11 | chvar 2298 | 1 ⊢ (𝑦 = 𝐴 → ⦋𝑦 / 𝑥⦌𝐵 = 𝐶) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 = wceq 1523 Ⅎwnfc 2780 ⦋csb 3566 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1762 ax-4 1777 ax-5 1879 ax-6 1945 ax-7 1981 ax-9 2039 ax-10 2059 ax-11 2074 ax-12 2087 ax-13 2282 ax-ext 2631 |
This theorem depends on definitions: df-bi 197 df-or 384 df-an 385 df-tru 1526 df-ex 1745 df-nf 1750 df-sb 1938 df-clab 2638 df-cleq 2644 df-clel 2647 df-nfc 2782 df-sbc 3469 df-csb 3567 |
This theorem is referenced by: disji2 4668 disjprg 4680 disjxun 4683 tfisi 7100 coe1fzgsumdlem 19719 evl1gsumdlem 19768 iundisj2 23363 disji2f 29516 disjif2 29520 iundisj2f 29529 iundisj2fi 29684 |
Copyright terms: Public domain | W3C validator |