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Mirrors > Home > MPE Home > Th. List > Mathboxes > bj-rexcom4a | Structured version Visualization version GIF version |
Description: Remove from rexcom4a 3330 dependency on ax-ext 2704 and ax-13 2355 (and on df-or 384, df-sb 2011, df-clab 2711, df-cleq 2717, df-clel 2720, df-nfc 2855, df-v 3306). This proof uses only df-rex 3020 on top of first-order logic. (Contributed by BJ, 16-Jun-2019.) (Proof modification is discouraged.) |
Ref | Expression |
---|---|
bj-rexcom4a | ⊢ (∃𝑥∃𝑦 ∈ 𝐴 (𝜑 ∧ 𝜓) ↔ ∃𝑦 ∈ 𝐴 (𝜑 ∧ ∃𝑥𝜓)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | bj-rexcom4 33096 | . 2 ⊢ (∃𝑦 ∈ 𝐴 ∃𝑥(𝜑 ∧ 𝜓) ↔ ∃𝑥∃𝑦 ∈ 𝐴 (𝜑 ∧ 𝜓)) | |
2 | 19.42v 1994 | . . 3 ⊢ (∃𝑥(𝜑 ∧ 𝜓) ↔ (𝜑 ∧ ∃𝑥𝜓)) | |
3 | 2 | rexbii 3143 | . 2 ⊢ (∃𝑦 ∈ 𝐴 ∃𝑥(𝜑 ∧ 𝜓) ↔ ∃𝑦 ∈ 𝐴 (𝜑 ∧ ∃𝑥𝜓)) |
4 | 1, 3 | bitr3i 266 | 1 ⊢ (∃𝑥∃𝑦 ∈ 𝐴 (𝜑 ∧ 𝜓) ↔ ∃𝑦 ∈ 𝐴 (𝜑 ∧ ∃𝑥𝜓)) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 196 ∧ wa 383 ∃wex 1817 ∃wrex 3015 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1835 ax-4 1850 ax-5 1952 ax-11 2147 |
This theorem depends on definitions: df-bi 197 df-an 385 df-ex 1818 df-rex 3020 |
This theorem is referenced by: bj-rexcom4bv 33098 bj-rexcom4b 33099 |
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